Numerical Analysis數值分析筆記 /
2.1 The Bisection Method /
習題組 2.1 /
NO.1.
use the bisetion method to find the $p_3$ for $f(x)=\sqrt{x}-\cos x $ on $[0,1]$.
- #include <stdio.h>
- #include <stdlib.h>
- #include <math.h> /**/
- float f(float x);
- int sig(float v);
- int main(void)
- {
- int i=0,N=100;
- float a=0.0,b=1.0,p=(a+b)/2,FA=0.0,FP=0.0;
- float TOL=0.00001;
- printf("n an bn pn f(pn)\n");
- /*Step1*/
- i=1;
- FA=f(a);
- /*Step2*/
- while(i<=N)
- { /*Step3*/
- p=a+(b-a)/2;
- FP=f(p);
- printf("%2d %.9f %.9f %.9f %+.9f\n",i,a,b,p,f(p));
- /*Step4*/
- if(FP==0 || (b-a)/2<TOL)
- {printf("n=%d, p=%+f\n",i,p);break;}
- /*Step5*/
- i=i+1;
- /*Step6*/
- if(sig(FA)*sig(FP)>0){a=p;FA=FP;}
- else b=p;
- }
- printf("method failed after N=%d iterations.",N);
- system("PAUSE");
- return 0;
- }
- float f(float x)
- {
- return sqrt(x)-cos(x);
- }
- int sig(float u)
- {
- if(u>0){return 1;}
- else if(u<0){return -1;}
- else {return 0;}
- }
c語言執行結果:
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